Normal distribution > Standardising
1234Standardising

Solutions to the exercises

Exercise 1
a

1006.6 gram.

b

μ = 1008 . 215 gram that is approximately 1008.2 gram.

c

σ = 1 . 4607 gram or approximately 1.5 gram.

Exercise 2
a

0 . 1056 1200 127 cars.

b

48.4206 or about 48.4 seconds.

c

2.1493 or about 2.1 seconds.

Exercise 3
a

66.87% (about 67%)

b

84.13% (about 84%)

c

There are several possibilities; for example μ = 10 . 01 and σ = 0 . 008 will result in 99.37% of screws being accepted.

Exercise 4
a

P ( l < 60 | μ = m and σ = s ) = 0 . 875 gives you ( 60 - m ) s 1 . 15 .
P ( l < 30 | μ = m and σ = s ) = 0 . 39 gives you ( 30 - m ) s - 0 . 28 .
Therefore: 60 - m = 1 . 15 s and 30 - m = - 0 . 28 s . Solve the equations to get m 39 . 5 and s 21 . 0 . The values are therefore μ 39 . 5 and σ 21 . 0 .

b

P ( l < g | μ = 35 . 9 and σ = 21 . 0 ) = 0 . 30 gives you g 24 . 9 . Therefore plants up to a length of about 25 cm are being destroyed.

Exercise 5
a

σ 60 . 8 gram

b

4,8%

c

1006.9 gram (about 1007 gram)

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